In our previous article on transformer vector groups, we mentioned the importance of the delta connections to determine whether the LV leads or lags the HV winding. The secret sauce is based on how the delta windings are connected.
There are two primary ways to configure these connections:
To illustrate how this affects phase displacement, we can break down the math behind a standard YNd11 connection.
A YNd11 transformer configuration dictates that the LV side leads the HV side by 30°. Here is how to decode the standard nomenclature:
| Symbol | Meaning |
| Y | Indicates that the High Voltage (HV) primary winding is connected in a Star (Wye) configuration. |
| N | Shows that the neutral point of the Star winding is brought out to a terminal (on the HV side for YNd11). |
| d | Indicates that the Low Voltage (LV) secondary winding is connected in a Delta configuration. |
| 11 | Represents the phase displacement between the HV and LV voltages. |
Using the clock-face method where 12 o’clock represents 0°, the HV line voltage serves as the 12 o’clock reference. The LV line voltage leads this reference, with “11” representing an advance of 30°. Because this is a leading connection, the LV side must be configured as a DAB connection.
We can mathematically prove this leading relationship using either currents or voltages. Let’s start by tracing the currents for a YNd11 transformer, assuming a 1:1 turns ratio for simplicity.
In a Wye connection, the line current equals the phase current. Setting our primary (HV) line currents as a perfectly balanced three-phase set with Phase A as the reference:
IA = 1∠0°
IB = 1∠-120°
IC = 1∠120°
Due to magnetic coupling, the primary winding’s current dictates the secondary winding’s current on the shared core leg. In YNd11 wiring, secondary Delta phase winding a shares a core leg with primary Wye phase A. Therefore, the Delta winding currents directly mirror the Wye line/phase currents:
Iaφ = 1∠0°
Ibφ = 1∠-120°
Icφ = 1∠120°
In a Delta configuration, the line current is the vector difference of the two phase currents meeting at that node. Applying Kirchhoff’s Current Law (KCL) at node a, the exiting line current (Ia) is calculated as follows:
Ia = Iaφ – Ibφ
Ia = 1∠0° – 1∠-120°
Ia = √3∠30°
By tracing these line currents, we see the primary line current of 1∠0° transforms to a secondary line current of √3∠30°. The secondary line current leads the primary by exactly 30°, which aligns perfectly with 11 o’clock on our phase dial.
Transformer vector groups specify the winding configurations and the phase displacement between the primary and secondary sides. According to the IEC 60076 standard (specifically IEC 60076-1, which covers general requirements for power transformers), the absolute main purpose of standardizing vector groups is to ensure the safe and reliable parallel operation of transformers.
While the vector group tells us exactly how the internal windings are physically connected, the standard emphasizes this classification primarily to prevent catastrophic failures when multiple transformers are connected to the same grid. To safely connect two or more transformers in parallel so they can share a load, their secondary voltages must peak at the exact same time. Here, we are talking about voltages, and wouldn’t it be more intuitive if we could demonstrate the mathematical proof using voltages instead of currents?
Before that, remember that vector groups are expressed in phase voltages (line-to-neutral) instead of line voltages. This was deliberately done in order to create a universal, mathematically consistent reference frame. Here is exactly why phase voltages are the only way to make the clock-face system work:
Now, consider the same transformer connection of YNd11 with a 1:1 turns ratio to keep the numbers clean. Let’s set our primary side (HV) phase voltages as a perfectly balanced three-phase set, using Phase A as the reference:
VAN = 1∠0°
VBN = 1∠-120°
VCN = 1∠120°
Because of magnetic coupling, the voltage across the primary winding dictates the voltage across the secondary winding sharing the same core leg. In standard YNd11 wiring, the secondary Delta phase winding a shares a core leg with the primary Wye phase A. Therefore, the Delta winding voltages directly mirror the Wye phase voltages.
It is important to know from what reference points we should measure the Delta winding voltages. To measure the voltage across the secondary Delta winding a, it should be between points a and c. This means the voltage VAN in the primary winding should be in phase with the voltage Vac in the secondary winding.
VAN → Vaφ → Vac = 1∠0°
The same is true for the Delta winding b (between points b and a), and Delta winding c (between points c and b).
VBN → Vbφ → Vba = 1∠-120°
VCN → Vcφ → Vcb = 1∠120°
When mapping the phase displacement between the primary and secondary windings onto our clock-face reference, we can clearly see that the ‘phantom’ neutral voltage of the delta winding aligns perfectly with the 11 o’clock position. Ultimately, this visual and mathematical confirmation proves that the delta side is actively leading the wye side by exactly 30°.
In a practical field scenario, physical connections are made directly at the line terminals. This raises a valid question: how can we definitively prove that the line voltages on the delta side genuinely lead the line voltages on the wye side?
Returning to the phase voltage reference values established earlier in our analysis, we have:
VAN = 1∠0°
VBN = 1∠-120°
VCN = 1∠120°
From these phase voltages, calculating the primary line voltages is straightforward:
VAB = VAN – VBN
VAB = 1∠0° – 1∠-120°
VAB = √3∠30°
Because this is a balanced three-phase system, the remaining line voltages are naturally displaced by 120°. Therefore:
VBC = √3∠-90°
VCA = √3∠150°
Transitioning to the delta side, our previous deductions established that:
Vac = 1∠0°
Vba = 1∠-120°
Vcb = 1∠120°
Consequently, the line voltage Vab is simply the inverse of Vba, which translates to a 180° phase shift:
Vab = -(Vba)
Vab = -(1∠-120°)
Vab = 1∠60°
Maintaining the principles of a balanced three-phase system displaced by 120°, we find the remaining secondary line voltages:
Vbc = 1∠-60°
Vca = 1∠180°
By comparing the primary line voltage VAB at ∠30° against the secondary line voltage Vab at ∠60°, we have mathematically proven that the line voltages on the delta side strictly lead the line voltages on the wye side by 30° for a standard YNd11 transformer vector group.
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